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To determine if the given equation is a linear equation, let's first see if we can rewrite it in standard form.
Ax+ By= C
This is the standard form of the given equation. Below we have highlighted how it corresponds to the general standard form. x-y=-5 ⇔ 1x+( -1)y= -5 When written this way, we can see that A= 1, B= -1, and C= -5. Since this equation can be written in standard form, it is linear.
Think of the point where the graph of an equation crosses the x-axis. The y-value of that ( x, y) coordinate pair is equal to 0, and the x-value is the x-intercept. To find the x-intercept of the given equation, we should substitute 0 for y and solve for x.
y= 0
Zero Property of Multiplication
.LHS /5.=.RHS /5.
An x-intercept of 4 means that the graph passes through the x-axis at the point ( 4,0).
Let's use the same concept to find the y-intercept. Consider the point where the graph of the equation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, substituting 0 for x will give us the y-intercept.
x= 0
Zero Property of Multiplication
.LHS /4.=.RHS /4.
A y-intercept of 5 means that the graph passes through the y-axis at the point (0, 5).
We can now graph the equation by plotting the intercepts and connecting them with a line.