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Substitute the information given into the rectangle area formula, then simplify.
Length: 18ft.
Width: 8ft.
When we are given the area of a rectangle, we generally need to use the formula for the area of a rectangle. In this case we need to write expressions for the length, l, and width, w.
| Verbal Expression | Algebraic Expression |
|---|---|
| the length is 10 ft more than the width | l = 10 + w |
Now that we have an algebraic expression, we can substitute. Then, let's see where we can go from there.
A= 144, l= 10 + w
Distribute w
LHS-144=RHS-144
Commutative Property of Addition
Rearrange equation
Now, we have a quadratic equation that is equal to zero. Let's look for two factors of -144 that have a sum of 10. Since ac is negative, the sign of the factors will be different. Furthermore, since b is positive, the factor with the larger magnitude will be positive too.
| Factors | Sum of factors |
|---|---|
| -1, 144 | 143 |
| -2, 72 | 70 |
| -3, 48 | 45 |
| -4, 36 | 32 |
| -6, 24 | 18 |
| -8, 18 | 10 |
We have found our factors that have a sum of 10. Since our leading coefficient is 1, we can use -8 and 18 directly as part of the factoring. w^2 + 10w-144=(w-8)(w+18) Let's set each factor equal to zero and solve for w.
Use the Zero Product Property
(I): LHS+8=RHS+8
(II): LHS-18=RHS-18
Since w represents a measurement of distance, we can ignore the negative solution and say the width of the rectangle is 8 ft. To find the length, we can add 10 to the width and get 18ft.