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Type of Function: Exponential
| Year | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| Value ($) | 18 500 | 15 910 | 13 682.60 | 11 767.04 | 10 119.65 |
Let's plot the ordered pairs ( 0, 18 500), ( 1, 15 910), ( 2, 13 682.60), ( 3, 11 767.04), and ( 4, 10 119.65).
The ordered pairs appear to represent an exponential function.
We can model the value y of the car after x years by using an exponential function.
y=ab^x
x= 1, y= 15 910
a^1=a
.LHS /18 500.=.RHS /18 500.
Calculate quotient
Rearrange equation
The constant multiplier is 0.86. Then, the function below models the data. y=18 500( b)^x ⇓ y=18 500( 0.86)^x
Therefore, the car is worth about $6436.66 after 7 years.