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Is there a greatest common factor between all of the terms in the given expression? If so, you should factor that out first.
(v+7)(v+9)
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
v^2+16v+63
In this case, we have 63. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative.)
| Factor Constants | Product of Constants |
|---|---|
| 1 and 63 | 63 |
| -1 and -63 | 63 |
| 3 and 21 | 63 |
| -3 and -21 | 63 |
| 7 and 9 | 63 |
| -7 and -9 | 63 |
Next, let's consider the coefficient of the linear term. v^2+16v+63 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 16.
| Factors | Sum of Factors |
|---|---|
| 1 and 63 | 64 |
| -1 and -63 | -64 |
| 3 and 21 | 24 |
| -3 and -21 | -24 |
| 7 and 9 | 16 |
| -7 and -9 | -16 |
We found the factors whose product is 63 and whose sum is 16. v^2+16v+63 ⇔ (v+7)(v+9)
Distribute (v + 9)
Distribute v
Distribute 7
Add terms
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!