Sign In
Get out a piece of paper and follow the directions provided.
Continue to follow the directions. Recall cutting out is like subtracting.
Once you cut the pieces, you can flip one of them to find the rectangle.
Use the answer from Part C for the binomials..
Consider the whole proces from Part A to Part D, notice that rearranging the area does not change it's value.
a^2 and b^2
a^2-b^2
Width: a-b
Length: a+b
A=(a+b)(a-b)
a^2-b^2=(a+b)(a-b) because when we subtract a square with side length b from a square with side length a, we can rearrange the pieces to get a rectangle with dimensions a+b and a-b. Rearranging the pieces of the remaining figure does not change the area.
Let's start this exploration by drawing the two squares as described in the directions.
The area of the large square with sides length a is a^2. The area of the The area of the small square with sides length b is b^2.
Let's cut the square out of the bottom corner.
Since the area of the larger square is a^2 and the smaller is b^2, by cutting the smaller one out, the remaining area is a^2-b^2.
Let's first draw the diagonal line from the outside to the inside corner of the new figure.
If we flip one of the two polygons over, we can match along the magenta colored side that we just cut.
From the two dimension shown, we can see that the length of the newly formed rectangle is a+b and the width is a-b.
From Part C, we determined that the length of the rectangle is a+b and its width is a-b. Since area is the product of the length and the width, let's multiply the two binomials to write an expression for the area.
First we can complete the statement with what we found in Part D.