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Is there a greatest common factor between all of the terms in the given expression? If so, you should factor that out first.
-(4x+5)(3x-4)
Here we have a quadratic trinomial of the form ax^2+bx+c, where |a| ≠1 and there are no common factors. To factor this expression, we will rewrite the middle term, bx, as two terms. The coefficients of these two terms will be factors of ac whose sum must be b.
- 12x^2+x+20 ⇔ -12x^2+1x+20
We have that a= -12, b=1, and c=20. There are now three steps we need to follow in order to rewrite the above expression.
c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result 240 &- 1 &240 + (-1) &239 120 &- 2 &120 + (-2) &118 80 &- 3 &240 + (-1) &239 40 &- 6 &40 + (-6) &34 30 &- 8 &30 + (-8) &22 24 &- 10 &24 + (-10) &14 20 &- 12 &20 + (-12) &8 16 & - 15 & 16 + ( - 15) &1
Finally, we will factor the last expression obtained.
Factor out 4x
Factor out 5
Factor out (-3x+4)
Factor out -1
Distribute - 1
Distribute (3x-4)
Subtract term
We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!