McGraw Hill Glencoe Algebra 1, 2012
MH
McGraw Hill Glencoe Algebra 1, 2012 View details
Standardized Test Practice

Exercise 2 Page 330

First find out how much Craig earns when working 40 hours a week.

H

Practice makes perfect

Let's write an inequality that describes Craig's desired earnings. The phrase at least is equivalent to saying greater than or equal to, which algebraically can be written as ≥. Therefore, we can describe Craig's desired earnings. Earnings≥ 600 Next, let's find how much money Craig earns in a week by working 40 hours. The pay rate is $12.80 per hour so we can find the total weekly earnings multiplying this rate by 40 hours. 40*12.80= 512 Craig can earn $512 in a week by working 40 hours but this is not enough to reach Craig's earnings goal, so he needs to put in overtime. We know that Craig is paid $19.20 per hour of overtime. So, if the extra number of hours Craig needs to put in to earn at least $600 is x, we can rewrite the left-hand side of our inequality with the expression 19.20x. 512+ 19.20x≥ 600 By solving this inequality for x we can determine the number of hours Craig has to put in.

512+19.20x ≥ 600
19.20x ≥ 88
h=4.853333...

We are only given whole hours as options, and since Craig wants to earn at least $600 we have to round up the number of extra hours Craig has to put in to 5 hours. In total Craig has to put in 45 hours, which corresponds to option H.