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If two lines intersect, their intersection is exactly one point.
This postulate is accepted without a proof.
Suppose that two lines have two points of intersection. For that to be true, one line would have to bend to cross the other line again.
This is not possible because lines are straight by definition. The only possibility for two lines to have more than one point of intersection is if the lines overlap. If this is true, the two lines would have infinitely many common points — they would be coincidental lines.
The postulate above, proposed by John Playfair, is an equivalent version of Euclid's Fifth Postulate.
Euclid's Fifth Postulate |
If a line segment crosses two lines in such a way that the sum of their interior angles on the same side is less than 180∘, then the lines will eventually meet. |
If a plane contains two points, then it contains the line passing through the points.
This postulate is accepted without a proof.
Consider two points on a plane and the line passing through them.
If the line is not contained in the plane, then there must be a point that lies on the line but not on the plane. Planes have infinite width and length but no height, so for this to be the case, the line must curve away from the plane.
However, a line is always straight — it cannot curve away from the plane. Therefore, if a plane contains two points, it must contain the line passing through them.
Given any three noncollinear points, there exists exactly one plane that contains them all.
This postulate is accepted without a proof.
This means that there is only one plane that passes through any three noncollinear points.