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Glencoe Math: Course 3, Volume 2

GM

Glencoe Math: Course 3, Volume 2 View details

2. Volume of Cones

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Exercise 1 Page 600

Use the formula for the volume of a cone.

$2668.3 m^{3}$

Practice makes perfect

Consider the given cone.

To find the volume, we can use the formula for the volume of a cone.

V = \frac{1}{3} π r^{2} h

Here,

r

is the radius and

h

is the height of the cone. We are given that the height of the cone is

13

meters. The radius of the base is

14

meters. Let's substitute these values into the formula and calculate the volume.

V = \frac{1}{3} π r^{2} h

$r = 14$ , $h = 13$

V = \frac{1}{3} π (14)^{2} (13)

▼

Simplify right-hand side

Calculate power

V = \frac{1}{3} π (196) (13)

Multiply

V = \frac{1}{3} π (2548)

CommutativePropMult

Commutative Property of Multiplication

V = \frac{1}{3} (2548 π)

MoveRightFacToNumOne

$\frac{1}{b} \cdot a = \frac{a}{b}$

V = \frac{2 5 4 8 π}{3}

Use a calculator

V = 2668.259360 \dots

Round to $1$ decimal place(s)

V \approx 2668.3

The volume of the cone is

2668.3

cubic meters.

Subchapter links

Guided Practice p.600

Independent Practice p.601-602

H.O.T. Problems p.602

Standardized Test Practice p.602-604

Extra Practice p.603

Common Core Review p.604