Glencoe Math: Course 3, Volume 2
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Glencoe Math: Course 3, Volume 2 View details
6. Changes in Dimensions
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Exercise 7 Page 645

Start by finding the volume and surface area of the model.

Volume: 15 049 359 360 cubic inches
Surface Area: 39 979 008 square inches

Practice makes perfect

We are given that the model of a new apartment building is in the shape of the following rectangular prism.

The model
We want to find the volume and surface area of the new building knowing that its size is 144 times the size of the model. Let's start by finding the volume and surface area of the model. Recall that the volume and surface area of a rectangular prism with length l, width w, and height h can be calculated using the following formulas. V & = l w h [0.3em] S.A. & = 2( l w + w h + l h)In this case, l = 18, w = 10, and h= 28. We can substitute these values into the formulas to calculate the volume and surface area of the model. We will start with the volume.
V=l wh
V= 18( 10)( 28)
V=5040
Next, we will calculate the surface area.
S.A.=2(l w + w h + l h)
S.A.=2[ 18( 10) + 10( 28) + 18( 28)]
S.A.=2(180+280+504)
S.A.=2(964)
S.A.=1928
Therefore, the volume of the model is 5040 cubic inches and the surface area is 1928 square inches. Now we can find the volume and surface area of the building using the fact that its size is 144 times the size of the model. To do so, recall the relationships between the volumes and the surface areas of similar solids.
Volume of Similar Solids If Solid X is similar to Solid Y by a scale factor, then the volume of X is equal to the volume of Y times the cube of the scale factor.
Surface Area of Similar Solids If Solid X is similar to Solid Y by a scale factor, then the surface area of X is equal to the surface area of Y times the square of the scale factor.

We know that the building and its model are similar and the scale factor is 144. This means that we can calculate the volume and surface area of the building using these relationships. Let's do it!

Object Volume, in^3 Surface Area, in^2
model 5040 1928
building 5040 * 144^3 = 15 049 359 360 1928 * 144^2 = 39 979 008

Therefore, the volume of the building is 15 049 359 360 cubic inches and the surface area is 39 979 008 square inches.