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Use the Converse of the Pythagorean Theorem.
3 - 5 - 7, see solution.
We are given four sets of numbers that represent the side measures of a triangle. We want to identify the set that does not belong with the other three. If we know the side measures of a triangle, we can check if it is a right triangle. Let's check which of the given measures represent a right triangle. We can use the Converse of the Pythagorean Theorem to help us.
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Converse of the Pythagorean Theorem |
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If the sides of a triangle have lengths a, b, and c and c^2=a^2+b^2, then the triangle is a right triangle. |
This tells us that we can use the Pythagorean Theorem in reverse to test if a triangle with the given side lengths is right. The hypotenuse c has the greatest value of the lengths of a right triangle. Let's substitute the side lengths from each set into a^2+b^2=c^2 and see if they produce a true statement.
| Set | a | b | c | a^2+b^2=c^2 | Simplify | True or False? |
|---|---|---|---|---|---|---|
| 3 - 4 - 5 | 3 | 4 | 5 | 3^2+ 4^2? = 5^2 | 25 = 25 | True |
| 12 - 35 - 37 | 12 | 35 | 37 | 12^2+ 35^2? = 37^2 | 1369 = 1369 | True |
| 3 - 5 - 7 | 3 | 5 | 7 | 3^2+ 5^2? = 7^2 | 34 ≠49 | False |
| 6 - 8 - 10 | 6 | 8 | 10 | 6^2+ 8^2? = 10^2 | 100 ≠100 | True |
Notice that the measures from the third set produced a false statement, while the first, second, and fourth sets produced a true statement. This means that the third set of numbers are not measures of the sides of a right triangle, while the other sets are. Now we can see that the third set does not belong with the other three sets.