Glencoe Math: Course 3, Volume 2
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Glencoe Math: Course 3, Volume 2 View details
6. Use the Pythagorean Theorem
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Exercise 5 Page 427

Practice makes perfect
We are given the following map.

We are asked to find the distance between Sycamore cabin and Oak cabin. Let's start by taking a closer look at the diagram.

The distance between Sycamore cabin and Oak cabin is also the length of a leg of a right triangle. This means that we can use the Pythagorean Theorem to find the missing length. a^2+ b^2= c^2 In the formula, a and b are the lengths of the legs and c is the length of the hypotenuse of a right triangle. We are given a triangle with a= 30 and c= 50.

Let's substitute these values into the formula. a^2+ b^2= c^2 ⇕ 30^2+ b^2= 50^2 Now we can solve the equation that we got to find the value of b.

a^2+b^2=c^2
30^2+b^2= 50^2
â–¼
Solve for b
900+b^2=2500
900+b^2-900=2500-900
b^2=1600
sqrt(b^2)=sqrt(1600)
b=sqrt(1600)
b=40

Since a negative side length does not make sense, we only need to consider positive solutions. Therefore, we got that the distance between Sycamore cabin and Oak cabin is 40 yards.

Let's consider the two following routes from Hickory cabin to Elm cabin.

We can write an expression for the length of each route.

Travel Route Distance (yards)
Direct Route 60
Through Mess Hall d+40
We know that a camper in Hickory cabin wants to go to Elm cabin. We want to calculate how much farther it is if she walks to the Mess Hall first. To do so, we need to find the value of d. Let's start by taking a closer look at the diagram.

Notice that the distance between Hickory cabin and the Mess Hall is also the length of a leg of a right triangle. To find this distance, we need to use the Pythagorean Theorem. a^2+ b^2= c^2 In the formula, a and b are the lengths of the legs and c is the length of the hypotenuse of a right triangle. We are given the triangle with a= 40, b= d, and c= 60.

Let's substitute these values into the formula. a^2+ b^2= c^2 ⇕ 40^2+ d^2= 60^2 Now we can solve an equation that we got to find the value of d.

a^2+b^2=c^2
40^2+ d^2= 60^2
â–¼
Solve for d
1600+d^2=3600
1600+d^2-1600=3600-1600
d^2=2000
sqrt(d^2)=sqrt(2000)
d=sqrt(2000)
d=44.721359...
d≈ 44.7

Since a negative side length does not make sense, we only need to consider positive solutions. Therefore, the distance between Hickory cabin and the Mess Hall is about 44.7 yards. Now we can compare the distances!

Travel Route Distance (yards)
Direct Route 60
Via Mess Hall d+40≈ 44.7+40=84.7

Let's calculate the difference between these distances. 84.7-60=24.7 Therefore, if the camper walks to the Mess Hall first, the trip will be about 24.7 yards farther than going directly to Elm cabin.