Glencoe Math: Course 3, Volume 2
GM
Glencoe Math: Course 3, Volume 2 View details
4. Polygons and Angles
Continue to next subchapter

Exercise 28 Page 404

The sum of the measures of the interior angles of a polygon is (n-2)180, where n represents the number of sides.

C

Practice makes perfect

We are given the following polygon.

We are asked to find the measure of angle AED. Let's start by recalling the rule for the sum of the measures of the interior angles of a polygon.

Interior Angle Sum of a Polygon

The sum of the measures of the interior angles of a polygon is (n-2)180, where n represents the number of sides.

To find the sum of the measures of the interior angles of a pentagon, we will substitute 5 for n in this expression.

(n-2)180
( 5-2)180
â–¼
Evaluate
(3)180
540

We got that the sum of the interior angles of a pentagon is 540^(∘). Note that in the given pentagon, there are three right angles. m∠ ABC = m∠ CDE = m∠ BAE = 90^(∘) We also know that angle AED is congruent to angle BCD. This means that these angles have the same measure. Therefore, the polygon has 5 interior angles, where 3 angles have the measure of 90^(∘) and 2 angles have the measure of x^(∘). Let's write an equation that represents this situation. 3* 90 ^(∘) + 2* x^(∘) = 540^(∘) Now we can solve this equation for x. For simplicity, we will not write the degree symbol.

3* 90 + 2* x= 540
270+2x=540
270+2x-270=540-270
2x=270
2x/2=270/2
2x/2=270/2
x=270/2
x=135

We got that x=135. This means that the measure of angle AED is equal to 135^(∘) and C is the correct option.