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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

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Exercise 1 Page 472

Start by using the Subtraction Property of Equality.

s=3

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Division Property of Equality.

13 = 1 + 4s

LHS-1=RHS-1

13 - 1 = 1 + 4s - 1

Subtract terms

12 = 4s

.LHS /4.=.RHS /4.

12/4 = 4s/4

Calculate quotient

3 = s

Rearrange equation

s = 3

The solution to the equation is s=3. We can check our solution by substituting it into the original equation.

13 = 1 + 4s

s= 3

13 ? = 1 + 4( 3)

Multiply

13 ? = 1 + 12

Add terms

13 = 13 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476