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Split into factors
Factor out 5
Here we have a quadratic trinomial of the form ak^2+bk+c, where |a| ≠ 1 and there are no common factors. To factor this expression, we will rewrite the middle term, bx, as two terms. The coefficients of these two terms will be factors of ac whose sum must be b. 2( 2k^2+7k+6 ) ⇕ 2( 2k^2+7k+6 ) We have that a= 2, b=7, and c=6. There are now three steps we need to follow in order to rewrite the above expression.
c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result 3 & 4 & 3 + 4 &7 2 &6 &2 +6 &8 1 &12 &1 + 12 &13
Split into factors
Factor out 2xy
Let's look closely at the trinomial between the parentheses. x^2+4x+3y Notice that we have one x^2-term, one x-term, and one y-term. If this expression could be factored further, we would have two factors, each with x within them. However, that way we would also have one xy-term which is not present. (ax+b)(cx+dy) ⇕ acx^2 + ad xy + bcx + bd y In our expression the terms containing x^2 and y are both non-zero, so neither a nor d can be equal to 0. Therefore, their product must also be non-zero. As such, since there is no xy-term in our trinomial, the expression cannot be factored any further. 2x^3y+8x^2y+6xy^2 ⇓ 2xy(x^2+4x+3y)