body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Core Connections Integrated II, 2015

CC

Core Connections Integrated II, 2015 View details

1. Section 11.1

Continue to next subchapter

Exercise 9 Page 602

The diameter and chord make two pairs of corresponding sides in similar triangles.

9.5 centimeters

Practice makes perfect

Let's add the given information to the diagram.

With this information we can find the length of EB. Also, we will label the length of ED as x.

The diameter, CD, and the chord, AB, form two pairs of corresponding sides in similar triangles.

With this information we can calculate the length of x.

x/6=10/4

LHS * 6=RHS* 6

x=10/4* 6

MoveRightFacToNum

a/c* b = a* b/c

x=60/4

Calculate quotient

x=15

Having found the length of x, we can find the diameter CD by adding the length of DE and CD. CD= 15+ 4=19 cm As we can see, the diameter is 19 centimeters, which means the radius is 9.5 centimeters.

Subchapter links

11.1.1 Prisms and Cylinders p.601-603

11.1.2 Volumes of Similar Solids p.605-607

11.1.3 Ratios of Similarity p.610-611