Core Connections Geometry, 2013
CC
Core Connections Geometry, 2013 View details
Chapter Closure

Exercise 115 Page 575

a The interior angles of a polygon can be calculated with the formula 180^(∘)(n-2). Let's substitute n=28 into the formula and simplify.

180^(∘)(n-2)
180^(∘)( 28-2)
180^(∘)(26)
4680^(∘)

b The interior angle and corresponding exterior angle of a polygon form a linear pair. Therefore, if the exterior angle of a regular polygon is 42^(∘), we can find the interior angle, θ, by equating the measure of these angles with 180^(∘) and solving for m∠θ.

m∠ θ + 42^(∘)= 180^(∘) ⇔ m∠ θ = 138^(∘)The interior angle is 138^(∘). Like in Part A, we can find the sum of a polygons interior angles by using the formula 180^(∘)(n-2). In a regular polygon, all angles have the same measure. Therefore, if one interior angle is 138^(∘) and we have n sides, we can write the following equation. 180^(∘)(n-2)=138^(∘) n Let's solve for n in this equation.

180^(∘)(n-2)=138^(∘) n
Solve for n
180^(∘) n-360^(∘) =138^(∘) n
180^(∘) n=138^(∘) n + 360^(∘)
42^(∘) n=360^(∘)
n=8.57142 ...
n≈ 8.57

Since we did not get an integer for n, this type of polygon is not possible.

c A pentagon is a quadrilateral with 5 sides. Assuming that the pentagon is regular, we can find the measure of each angle by substituting n=5 in the formula 180^(∘)(n-2)n and simplifying. However, it is not stated that the polygon is regular, so we cannot find the interior angles.

d Using the same formula as in Part C we can find the measure of each interior angle in the regular decagon, which is a polygon with 10 congruent sides.

180^(∘)(n-2)/n
180^(∘)( 10-2)/10
Simplify
180^(∘)(8)/10
1440^(∘)/10
144^(∘)