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System (2): (2,- 6)
y_p=-1/2x+3
Explanation: See solution.
(II): Add (I)
(II): Remove parentheses
(II): Add and subtract terms
(II): .LHS /2.=.RHS /2.
(II): Add (I)
(II): Remove parentheses
(II): Add and subtract terms
(II): LHS+4x=RHS+4x
(II): .LHS /6.=.RHS /6.
Now we can start writing the equations. |c|c|c|c| Line &Equation & m & b q&y= mx+ 8 & m & 8 p&y= mx+ 3 & m & 3 We also have to find the lines slope. If we divide the vertical distance by the horizontal distance between two identifiable points on each graph, we can determine the slopes.
Now we can complete the equations. |c|c|c|c| Line &Equation & m & b [0.2em] [-0.8em] q&y= - 1/2x+ 8 & - 1/2 & 8 [0.8em] [-0.8em] p&y= 2x+ 3 & 2 & 3 [0.3em]
(I): y= 2x+8
(I): LHS-3=RHS-3
(I): LHS * (- 2)=RHS* (- 2)
(I): LHS+4x=RHS+4x
(I): .LHS /5.=.RHS /5.
(I): Rearrange equation
We are correct.