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_2P_1=2!/1!=2! When Kristen has picked a seat we have seven seats left. Notice that the order in which the friends sit matters. As each person picks a seat, the number of seats subtracts by 1. Therefore, the number of arrangements can be expressed as 7! after Kristen has made her choice.
The total number of arrangements is the product of 2! and 7!. Let's calculate this. 2!* 7!=10 080
Next, we will find the number of arrangements where 3 girls occupy the three seats on the row's right-hand side. This can be expressed as _3P_3. _3P_3=3!/( 3- 3)! ⇔ _3P_3=6 In the same way, we can find the number of arrangements with the 5 boys on the left-hand side. _5P_5=5!/( 5- 5)! ⇔ _5P_5=120 The total number of arrangements, where the girls are on the right-hand side and the boys on the left-hand side, is the product of the number of ways the girls can be arranged and the number of ways the boys can be arranged. If we divide this by the total arrangements, we can calculate the probability. _3P_3* _5P_5/_8P_8 =6* 120/40 320≈ 1.8 %
In this formula, n is the number of items and r_1, r_2,... is the number of times that item 1, item 2, and so on repeats. As already explained there are 8 names, which means n= 8. Also, there are 2 names that begin with K and 3 that begins with S. This means we have r_1= 2. and r_2= 3. 8!/2! 3! Let's calculate this on a graphing calculator.
There are 3360 ways for the group of friends to sit down with respect to the first letter of their last name.