body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Dashboard

Core Connections: Course 3 View details

Chapter Closure

Finish the assignment

Exercise 77 Page 180

Gather all of the variable terms on one side of the equation and all of the constant terms on the other.

x=3

To solve an equation, we first gather all of the variable terms on one side and all of the constant terms on the other using the Properties of Equality. In this case, we will start by using the Distributive Property to simplify the left-hand side of the equation.

2-(3x-4)=2x-9

Distr

Distribute - 1

2-3x+4=2x-9

AddTerms

Add terms

6-3x=2x-9

Now we can continue to solve using the Properties of Equality.

6-3x=2x-9

AddEqn

LHS+3x=RHS+3x

6-3x+3x=2x-9+3x

AddTerms

Add terms

6=5x-9

AddEqn

LHS+9=RHS+9

6+9=5x-9+9

AddTerms

Add terms

15=5x

RearrangeEqn

Rearrange equation

5x=15

DivEqn

.LHS /5.=.RHS /5.

5x/5=15/5

CalcQuot

Calculate quotient

x=3

Extra

Learn More!

Are you having trouble learning how to solve equations? Would you like to see why the Properties of Equality work? Do real-world examples help you understand more about the why and how of math topics? If you answered Yes to any of these questions, check out the Mathleaks courses related to this topic!

Subchapter links

Exercises

Exercise 77 Page 180

Hints

Check the answer

Extra