Core Connections: Course 1
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1. Section 7.1
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Exercise 20 Page 325

Use the formulas for perimeter and area of a rectangle.

12 23 inches

Practice makes perfect

We are given a rectangle with an area of 8 14 square inches.

A rectangle has two pairs of equal sides, so we can find its perimeter using the following formula. P=2l+2wIn this formula, l is the length and w is the width. From the picture, we know that l is equal to 4 12 inches. To calculate the perimeter we also need the value of w. Because we know the area and the length, we can use the formula for the area of a rectangle to find the value of the width. A=l * w We will substitute A=8 14 and l=4 12 into the formula. Then, we will write the mixed numbers as fractions.

A=l * w
8 14= 4 12* w
8* 4 +1/4=4* 2+1/2 * w
32 +1/4=8+1/2 * w
33/4=9/2 * w

Now, we will solve the resulting equation for w.

33/4=9/2 * w
334/92=92 * w/92
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Solve for w
334/92=92 * w/92
334/92=w
33/4* 2/9=w
33* 2/4* 9=w
66/36=w

Next, we can reduce this fraction by 6.

66/36=w
66/ 6/36/ 6=w
11/6=w
w=11/6

We found that the width of the given rectangle is 116 inches. Now that we have the length and the with, we can substitute l= 92 and w= 116 into the perimeter's formula. Let's do it!

P=2l+2w
P=2* 9/2 + 2* 11/6
P=2* 9/2+2* 11/6
P=18/2+22/6

When adding or subtracting fraction, they should have the same denominator. In this exercise, we have two fractions with different denominators. Since 6 is a multiple of 2, we can multiply both the numerator and denominator of 182 by 3 to create a common denominator.

P=18/2+22/6
P=18* 3/2* 3+22/6
P=54/6+22/6
P=54+22/6
P=76/6
P=76/ 2/6/ 2
P=38/3

Finally, let's rewrite the fraction as a mixed number.

P=38/3
P=36+2/3
P=36/2+2/3
P=12+2/3
P=12 23

The rectangle's perimeter is 12 23 inches.