Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 9.2
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Exercise 57 Page 465

Practice makes perfect
a

We can simplify the given expression by combining like terms. This involves treating the imaginary unit i like a variable. Let's do it!

a+b
2+3i+ 1-i
2+1+3i-i
3+2i

b

We will again treat i as though it was a variable and combine like terms. Let's go!

a-b
2+3i-( 1-i)
2+3i-1+i
2-1+3i+i
1+4i

c

To evaluate the product of 2 complex numbers, multiply them like polynomials. Recall that i^2 = -1.

ab
( 2+3i)( 1-i)
2+3i-i(2+3i)
2+3i-2i-3i^2
2+3i-2i-3(-1)
2+3i-2i+3
2+3+3i-2i
5+i

d

Let's substitute our values into the given quotient expression.

a/b ⇔ 2+3i/1-i Recall that the number pairs x+yi and x-yi are complex conjugates. To write the complex conjugate of a complex number, we only change the sign of the imaginary part. Let's do that for the denominator of our given expression now. Denominator:& 1-i Complex Conjugate:& 1+i The product of complex conjugates is a real number. We can multiply the numerator and the denominator by the complex conjugate of the denominator to write the given quotient as a complex number. 2+3i/1-i *1+i/1+i This process is also known as rationalizing the denominator and will simplify the quotient. Let's do it!

2+3i/1-i *1+i/1+i
(2+3i)(1+i)/(1-i)(1+i)
â–¼
Simplify numerator
2+3i+i(2+3i)/(1-i)(1+i)
2+3i+2i+3i^2/(1-i)(1+i)
2+3i+2i+3(-1)/(1-i)(1+i)
2+3i+2i-3/(1-i)(1+i)
-1+5i/(1-i)(1+i)
â–¼
Simplify denominator
-1+5i/1-i+i(1-i)
-1+5i/1-i+i-i^2
-1+5i/1-i+i-(-1)
-1+5i/1-i+i+1
-1+5i/2
â–¼
Simplify
-1/2+5i/2
-1/2+5i/2
-1/2+5/2i