aExponential decay is a decrease by the same factor over equal time periods.
B
b Exponential decay can be described using the equation y=abt where b is between 0 and 1.
C
c Use the equation from Part A and substitute 4 for t.
D
d Substitute 6000 for y and solve the resulting equation.
E
e Substitute -2.7 for t.
A
a See solution.
B
by=23500(0.8)t
C
c About $9600
D
d About 6.1 years
E
e About $43000
Practice makes perfect
a This is an example of exponential decay. This means that the car's value can be described by an exponential function with a multiplier b that is between 0 and 1.
y=abx
Since the car decreases annually by 20%, we have a multiplier of b=0.8.
y=a(0.8)x
b From Part A, we have already written half the function. We are only missing the initial value. In Part B, we have been given this value as a=23500.
y=23500(0.8)t
c By substituting t=4 into the function from Part B, we can determine the car's worth in four years.
Thus, approximately 6.1 years from now the car will be worth $6000.
e When t=0, the car's value is $23500. We want to know what the car was worth when it was new, which was 2.7 years ago. We can find that by substituting -2.7 for t in the equation.
Mathleaks uses cookies for an enhanced user experience. By using our website, you agree to the usage of cookies as described in our policy for cookies.