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Find the measures of the other two angles in â–³ CPM using vertical angles and the Alternate Exterior Angles Theorem.
∠CPM=60^(∘)
Examining the diagram, we can identify a couple of relationships.
Let's mark this information in the diagram.
(I):LHS-2x=RHS-2x
(I):Rearrange equation
(I):LHS+y=RHS+y
(II):x= 4y
Having solved for y, we substitute this back into the first equation to calculate x.
When we know that x= 20^(∘) and y= 5^(∘), we can calculate ∠MCP and ∠CMP. ∠MCP = 4( 20^(∘)) - 3( 5^(∘)) = 65^(∘) ∠CMP = 2( 20^(∘)) + 3( 5^(∘)) = 55^(∘) Now we know two angles in △ CPM.
Finally, we want to find ∠CPM. By the Triangle Angle Sum Theorem, the sum of the angles in △ CPM equals 180^(∘). Therefore, we can write an equation with the angles in △ CPM and solve for ∠CPM.