Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 4.2
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Exercise 103 Page 201

Find the measures of the other two angles in △ CPM using vertical angles and the Alternate Exterior Angles Theorem.

∠ CPM=60^(∘)

Practice makes perfect

Examining the diagram, we can identify a couple of relationships.

Let's mark this information in the diagram.

Congruent angles have the same measure which means we can set the angle's expressions equal to each other. Therefore, we can write two equations and If we combine them, we get a system of equations. 2x+3y = 3x-y 4x-3y= 65^(∘) To solve the system, we will use the Substitution Method. Solve the first equation for x and substitute it into the second one.
2x+3y=3x-y & (I) 4x-3y=65^(∘) & (II)
(I): Solve for x
3y=x-y 4x-3y=65
x-y=3y 4x-3y=65
x=4y 4x-3y=65
x=4y 4( 4y)-3y=65
(II): Solve for y
x=4y 16y-3y=65
x=4y 13y=65
x=4y y=5
Having solved for y, we substitute this back into the first equation to calculate x.
x=4y y=5
x=4( 5) y=5
x=20 y=5
When we know that x= 20^(∘) and y= 5^(∘), we can calculate ∠ MCP and ∠ CMP. ∠ MCP = 4( 20^(∘)) - 3( 5^(∘)) = 65^(∘) ∠ CMP = 2( 20^(∘)) + 3( 5^(∘)) = 55^(∘) Now we know two angles in △ CPM.
Finally, we want to find ∠ CPM. By the Triangle Angle Sum Theorem, the sum of the angles in △ CPM equals 180^(∘). Therefore, we can write an equation with the angles in △ CPM and solve for ∠ CPM.
∠ CPM + 55^(∘) + 65^(∘) = 180^(∘)
∠ CPM + 120^(∘) = 180^(∘)
∠ CPM = 60^(∘)