Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 10.1
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Exercise 9 Page 504

Practice makes perfect
a

Explicit formulas for arithmetic sequences follow a specific format.

t( n)=t( 1)+( n-1) dIn this form, t( 1) is the first term in a given arithmetic sequence, d is the common difference from one term to the next, and t( n) is the {\color{#FF0000}{n}}^\text{th} term in the sequence. For this exercise, the first term is t( 1)= 3. Let's consider the other terms to determine the common difference d. 3+7 →10+7 →17... The common difference is d = 7. By substituting these two values into the explicit equation and simplifying, we can find the formula for this sequence.

t(n) = t(1) + (n-1)d
t(n) = 3 + (n-1) 7
t(n) = 3 + 7n - 7
t(n)=7n-4

b

We will solve this part the same way we solved Part A. For this part, the first term is t( 1) = 20. Let's continue by finding the common difference.

10-9 →11-9 →2... The common difference is d = -9. By substituting these two values into the explicit equation and simplifying, we can find the formula for this sequence.

t(n) = t(1) + (n-1)d
t(n) = 20 + (n-1)( -9)
t(n) = 20 -9n+9
t(n)=-9n+29