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Core Connections Algebra 1, 2013
CC
Core Connections Algebra 1, 2013 View details
1. Section 2.1
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Exercise 7 Page 47

Practice makes perfect
a

To evaluate the algebraic expression, we have to substitute the given value for r and s into the expression and follow the order of operations when simplifying.

sqrt(s)+|r|
SubstituteII

r= - 3, s= 4

sqrt(4)+| - 3|
CalcRoot

Calculate root

2+|- 3|
AbsNeg

|-3|=3

2+3
AddTerms

Add terms

5
b

Like in Part A, we substitute the given value for r, s, and t in the expression and evaluate according to the order of operations.

s-r/t
SubstituteValues

Substitute values

4-(- 3)/- 7
SubNeg

a-(- b)=a+b

4+3/- 7
AddTerms

Add terms

7/- 7
MoveNegDenomToFrac

Put minus sign in front of fraction

- 7/7
QuotOne

a/a=1

- 1
c

We substitute the given values for r, s, and t in the expression and evaluate according to the order of operations.

2s^3+r-t
SubstituteValues

Substitute values

2(4)^3+(- 3)-(- 7)
CalcPow

Calculate power

2(64)+(- 3)-(- 7)
Multiply

Multiply

128+(- 3)-(- 7)
AddNeg

a+(- b)=a-b

128-3-(- 7)
SubNeg

a-(- b)=a+b

128-3+7
AddSubTerms

Add and subtract terms

132
d

We substitute r and t into the expression and then follow the order of operations when simplifying.

sqrt(2(t-r))
SubstituteII

r= - 3, t= - 7

sqrt(2( - 7-( - 3)))
SubNeg

a-(- b)=a+b

sqrt(2(- 7+3))
AddTerms

Add terms

sqrt(2(- 4))
MultPosNeg

a(- b)=- a * b

sqrt(- 8)
CalcRoot

Calculate root

- 2
Subchapter links expand_more
arrow_right 2.1.1 Seeing Growth in Linear Representations p.47-48
6
7
8
Seeing Growth in Linear Representations 9 (Page 48)
Seeing Growth in Linear Representations 10 (Page 48)
arrow_right 2.1.2 Slope p.52-53
19
Slope 20 (Page 52)
21
Slope 22 (Page 52)
23
24
arrow_right 2.1.3 Comparing Δy and Δx p.57
31
Comparing Δy and Δx 32 (Page 57)
33
34
35
arrow_right 2.1.4 y=mx+b and More on Slope p.61-62
41
42
43
44
y=mx+b and More on Slope 45 (Page 62)