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Does either of the equations have an isolated variable in it?
(1,5)
When solving a system of equations using the Substitution Method, there are three steps.
For this exercise, y is already isolated in both equations, so we can skip straight to solving! Since the expression equal to y in (II) is simpler, let's use that for our initial substitution.
(I):y= 5x
(I):LHS-2x=RHS-2x
(I): Commutative Property of Addition
(I): Subtract terms
(I): .LHS /3.=.RHS /3.
(I): a* b/c=a/c* b
(I): a/a=1
(I): Identity Property of Multiplication
Great! Now, to find the value of y, we need to substitute x=1 into either one of the equations in the given system. Let's use the second equation.
The solution, or point of intersection, to this system of equations is the point (1,5).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= 1, y= 5
(I), (II): Identity Property of Multiplication
(I): Add terms
Because both equations are true statements, we know that our solution is correct.