Cumulative Assessment
Sign In
A bisector cuts a segment in half.
l, n, and m
| Segment | Expression | Substitute x with 3 | = |
|---|---|---|---|
| AB | x+1 | 3+1 | 4 |
| BC | 6(4-x) | 6(4- 3) | 6 |
| CD | 4x-6 | 4( 3)-6 | 6 |
| DE | 2(5x-7)-8 | 2(5( 3)-7)-8 | 8 |
| EF | 3(5-x)+2 | 3(5- 3)+2 | 8 |
Having calculated each of the smaller segments, we can list l as a bisector of BC and CD. We can also list n as a bisector of DE and EF. Finally, we can also list m as a bisector of AD and DF because the smaller segments that make up each of these add up to the same measure, 16.
