Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
2. Bisectors of Triangles
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Exercise 33 Page 317

To find the circumcenter, find the intersection of two perpendicular bisectors of two sides of the triangle.

(35/6, -11/6)

Practice makes perfect

Let's start by graphing the triangle using the given coordinates.

To find the circumcenter, we need to find the intersection of the perpendicular bisectors of the sides of the triangle. This means that we need to know the equations of at least two of them. Recall that a bisector cuts something in half, so we want to find lines that are perpendicular to the sides at their midpoints.

Finding Perpendicular Bisectors

Since we can find perpendicular bisectors of any of two sides, let's do it for AB and AC. Let's first find their midpoints. To do so, we can use the Midpoint Formula.

Side Points M(x_1+x_2/2,y_1+y_2/2) Midpoint
AB ( 2,5), ( 6,6) D(2+ 6/2,5+ 6/2) D(4,11/2)
AC ( 2,5), ( 12,3) E(2+ 12/2,5+ 3/2) E(7,4)

Let's add these midpoints to our graph.

Once we know the midpoints, we are ready to find the equations of our perpendicular bisectors.

Perpendicular Bisector of AB

According to the Slopes of Perpendicular Lines Theorem, the product of the slopes of perpendicular lines is -1. Let's find the slope of AB first. Since we know the endpoints of AB, we can find its slope using the Slope Formula. m = y_2-y_1/x_2-x_1 Let's substitute the given endpoints A( 2,5) and B( 6,6).
m_(AB) = y_2-y_1/x_2-x_1
m_(AB)=6- 5/6- 2
m_(AB)=1/4
We found that the slope of AB is 14. Now we can find the slope of the perpendicular bisector from the product. Let's call it m_(p_1). 1/4* m_(p_1) = -1 ⇔ m_(p_1) = -4 The slope of the perpendicular bisector of AB is -4. y=-4x+b To complete its equation, we need the y-intercept. We can use the fact that the line passes through the midpoint D( 4, 112).
y=-4 x+b
11/2=-4( 4)+b
â–Ľ
Solve for b
11/2=-16+b
11/2+16=b
11/2+32/2=b
43/2=b
b=43/2
Therefore, the equation of the perpendicular bisector of AB is y=-4 x+ 432.

Perpendicular Bisector of AC

Similarly, we can find the equation of the perpendicular bisector of AC. Let's first find the slope of AC using the Slope Formula and the given end points A( 2, 5) and C( 12,3).
m_(AC) = y_2-y_1/x_2-x_1
m_(AC)=3- 5/12- 2
â–Ľ
Simplify right-hand side
m_(AC)=-2/10
m_(AC)=-2/10
m_(AC)=-1/5
Once we know the slope of AC, we can find the slope of its perpendicular bisector from the product. Let's call it m_(p_2) -1/5* m_(p_2) = -1 ⇔ m_(p_2) = 5 The slope of the perpendicular bisector of AC is 5. y=5x+b Once again, to complete its equation, we can substitute the coordinates of its midpoint E(7,4).
y=5x+b
4=5( 7)+b
â–Ľ
Solve for b
4=35+b
-31=b
b=-31
Therefore, the equation of the perpendicular bisector of AC is y=5x-31.

Finding the Circumcenter

We want to find the intersection of the two perpendicular bisectors that we found. To do it, we need to solve the system of their equations. y=-4 x+43/2 y=5x-31 We can solve it by substituting y=-4 x+ 432 in the second equation.
y=-4 x+43/2 & (I) y=5x-31 & (II)
y=-4 x+43/2 -4 x+43/2=5x-31
â–Ľ
(II): Solve for x
y=-4 x+43/2 43/2=9x-31
y=-4 x+43/2 31+43/2=9x
y=-4 x+43/2 62/2+43/2=9x
y=-4 x+43/2 105/2=9x
y=-4 x+43/2 105/18=x
y=-4 x+43/2 35/6=x
y=-4 x+43/2 x=35/6
We found that x= 356. Now we can substitute it to the first equation to find the value of y.
y=-4 x+43/2 x=35/6
y=-4( 35/6)+43/2 x=35/6
â–Ľ
(I): Solve for y
y=- 1406+ 432 x= 356
y=- 1406+ 1296 x= 356
y=- 116 x= 356
Therefore, the coordinates of the circumcenter are ( 356,- 116).