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What makes a quadrilateral a rectangle? What is true for it's opposite sides? Adjacent sides?
See solution.
Let's label the vertices with their coordinates.
If this quadrilateral is a rectangle, three conditions have to be meet:
If opposite sides are parallel, they have the same slope. We can investigate this by using the Slope Formula.
Side | Points | y_2-y_1/x_2-x_1 | m |
---|---|---|---|
AB | ( 4,7), ( 2,5) | 7- 5/4- 2 | 1 |
DC | ( 7,4), ( 5,2) | 7- 5/4- 2 | 1 |
AD | ( 5,2), ( 2,5) | 2- 5/5- 2 | - 1 |
BC | ( 7,4), ( 4,7) | 4- 7/7- 4 | - 1 |
Since opposite sides have the same slope, they are parallel. Next, we have to prove that opposite sides have equal lengths. For this purpose, we use the Distance Formula.
Distance | Points | sqrt((x_2-x_1)^2+(y_2-y_1)^2) | d |
---|---|---|---|
AB | ( 4,7), ( 2,5) | sqrt(( 4- 2)^2+( 7- 5)^2) | sqrt(8) |
DC | ( 7,4), ( 5,2) | sqrt(( 7- 5)^2+( 4- 2)^2) | sqrt(8) |
AD | ( 5,2), ( 2,5) | sqrt(( 5- 2)^2+( 2- 5)^2) | sqrt(18) |
BC | ( 7,4), ( 4,7) | sqrt(( 7- 4)^2+( 4- 7)^2) | sqrt(18) |
As we can see, opposite sides also have the same length. Therefore, we know that AB≅ DC and AD≅ BC.
Let's also investigate the last criteria. Perpendicular lines have slopes that are opposite reciprocals of each other. This means the product of their slopes equals - 1. Let's test this.
Sides | Slopes | m_1* m_2=- 1 | Simplify | Perpendicular? |
---|---|---|---|---|
AB, AD | m_(AB)= 1, m_(AD)= - 1 | 1( - 1)? =- 1 | - 1 = - 1 | Yes |
DC, AD | m_(DC)= 1, m_(AD)= - 1 | 1( - 1)? =- 1 | - 1 = - 1 | Yes |
AD is perpendicular to both AB and DC. Additionally, since AD is parallel to BC which means AB and DC are perpendicular to BC as well.
Now we have proven that ABCD is a rectangle.