Big Ideas Math Algebra 2, 2014
BI
Big Ideas Math Algebra 2, 2014 View details
Cumulative Assessment

Exercise 1 Page 152

Find the equation of the related quadratic function. Then, determine the sign of the inequality using a test point.

B

Practice makes perfect

To write the quadratic inequality shown on the graph, we need to do two things.

  1. Find the equation of the related function.
  2. Determine the sign of the inequality.

Equation of the Related Function

We will use the factored form of a quadratic function to write our related function. y=a(x-p)(x-q) In the above equation, p and q are the roots and a is the leading coefficient of the function. Let's consider the given parabola.

We see above that the roots of the graph are x=- 3 and x=2. Thus, we have that p=- 3 and q=2. We can partially write the equation of the function. y=a(x-(- 3))(x-2) ⇔ y=a(x+3)(x-2) To find the value of a, we will use one of the points on the parabola. Let's use (1,- 4). Since this point is on the parabola, we know it satisfies its equation. We will substitute 1 and - 4 for x and y, respectively, and solve for a.

y=a(x+3)(x-2)
-4=a( 1+3)( 1-2)
Solve for a
-4=a(4)(- 1)
- 4=a(- 4)
1=a
a=1

Now we can write the complete equation of the parabola. y=1(x+3)(x-2) ⇔ y=(x+3)(x-2) This is the factored form of the related equation, but all of our answer choices are given in standard form. Therefore, we will convert this equation to standard form.

y=(x+3)(x-2)
Simplify
y=x(x-2)+3(x-2)
y=x^2-2x+3(x-2)
y=x^2-2x+3x-6
y=x^2+x-6

Sign of the Inequality

To determine the sign of the inequality, we can use a test point. For simplicity, we will use (0,0). Since this point is included in the shaded region, we know it satisfies the inequality.

Notice that the curve is solid, so our inequality will not be strict.

y ? x^2+x-6
0 ? ( 0)^2+ 0-6
0 ? 0+0-6
0 ? - 6
0 ≥ - 6

With the sign, we can finish writing the quadratic inequality. y ≥ x^2+x-6 This corresponds to option B.