Exercise 1 Page 373

To graph the function we will make a table of values. Make sure to include x-values to the left and to the right of the axis of symmetry. In our case, the axis of symmetry is x=0 and the vertex is the point (0,0).

x	7x^2	p(x)=7x^2
- 2	7( - 2)^2	28
- 1	7( - 1)^2	7
0	7( 0)^2	0
1	7( 1)^2	7
2	7( 2)^2	28

Now let's draw the parabola that connects the obtained points and the vertex. We can also draw the axis of symmetry x=0 and the parent function f(x)=x^2.

From the graph above, we can note the following:

Both graphs open up.
Both graphs have the same axis of symmetry, x=0.
The graph of the given function is narrower than the graph of the parent function.
Both graphs have the same vertex (0,0).

From the graph and the observations above, we can conclude that the graph of p is a vertical stretch by a factor of 7 of the graph of f.