Big Ideas Math Algebra 1, 2015
BI
Big Ideas Math Algebra 1, 2015 View details
Chapter Test
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Exercise 15 Page 473

Practice makes perfect
a Let's analyze the given function.
y=- 0.005x^2+0.17x+3 The variable y represents the height in feet of a tennis ball x feet from where you hit the ball. We are asked to find the maximum height of the ball. The given function is in the form of y= ax^2+bx+c. Let's begin by highlighting the coefficients. f(t)= - 0.005t^2+0.17t+3 Since the coefficient a is negative, the given quadratic function opens downward. Therefore, its maximum value will be at the vertex. First we will find the x-coordinate of the vertex. It can be found by using the formula x=- b2 a.
x=-b/2 a
t=-0.17/2( - 0.005)
Simplify
x=-0.17/- 0.005
x=0.17/0.005
x=17
The ball reaches its maximum height at x=17. Let's now find the maximum height by substituting x=17 into the given function.
y=- 0.005x^2+0.17x+3
y=- 0.005( 17)^2+0.17( 17)+3
Simplify
y=- 0.005(289)+0.17(17)+3
y=- 1.445+2.89+3
y=4.445
The maximum height of the ball is 4.445 feet.
b We are standing 30 feet from the net, which is 3 feet high. Therefore, the ball will clear the net if at x=30 the height of the ball is greater than 3 feet. Let's substitute x=30 into the given function and check!
y=- 0.005x^2+0.17x+3
y=- 0.005( 30)^2+0.17( 30)+3
Simplify
y=- 0.005(900)+0.17(30)+3
y=- 4.5+5.1+3
y=3.6
Since for x=30 the height of the tennis ball is 3.6 feet, which is greater than the height of the net, the ball will clear the net.