Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
1. Measures of Center and Variation
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Exercise 22 Page 591

Practice makes perfect
a We want to find the range, and the standard deviation of the given data set.

8.2 , 10.1 , 2.6 , 4.8 , 2.4 , 5.6 , 7.0 , 3.3 Let's find each statistic one at a time!

Range

The range is the difference between the greatest and least values in a set of data. For our exercise, the greatest value is 10.1 and the least value is 2.4. Range: 10.1- 2.4=7.7

b To calculate the standard deviation, calculate the mean first. Let's do it!

Mean

The mean of a data set is calculated by finding the sum of all values in the set and then dividing by the number of values. In this case, there are 8.
Mean=Sum of values/Number of values
Mean=8.2+10.1+2.6+4.8+2.4+5.6+7.0+3.3/8
Mean=44/8
Mean=5.5

We found out that x=5.5.

Standard Deviation

The standard deviation of a set of data is the average amount by which each individual value deviates or differs from the mean. Standard Deviation sqrt((x_1-x )^2 + (x_2-x )^2 + ... + (x_n-x )^2/n) In the above formula, x_1, ... ,x_n are the values of the set of data, x is the mean, and n is the number of values. We have 8 values and the mean is x= 5.5. Let's use this value and apply the formula to each value in the set.

x_n x_n-x (x_n-x)^2
8.2 8.2-5.5=2.7 2.7^2=7.29
10.1 10.1-5.5=4.6 4.6^2= 21.16
2.6 2.6-5.5=- 2.9 (- 2.9)^2=8.41
4.8 4.8-5.5=0.7 0.7^2=0.49
2.4 2.4-5.5=- 3.1 (- 3.1)^2=9.61
5.6 5.6-5.5= 0.1 0.1^2=0.01
7.0 7.0-5.5=1.5 1.5^2=2.25
3.3 3.3-5.5=- 2.2 (- 2.2)^2=4.84
Sum of Values 54.06

Finally, since n= 8, we need to divide by 8 and then calculate the square root. Standard Deviation: sqrt(54.06/8) ≈ 2.60