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8.2 , 10.1 , 2.6 , 4.8 , 2.4 , 5.6 , 7.0 , 3.3 Let's find each statistic one at a time!
The range is the difference between the greatest and least values in a set of data. For our exercise, the greatest value is 10.1 and the least value is 2.4. Range: 10.1- 2.4=7.7
Substitute values
Add terms
Calculate quotient
We found out that x=5.5.
The standard deviation of a set of data is the average amount by which each individual value deviates or differs from the mean. Standard Deviation sqrt((x_1-x )^2 + (x_2-x )^2 + ... + (x_n-x )^2/n) In the above formula, x_1, ... ,x_n are the values of the set of data, x is the mean, and n is the number of values. We have 8 values and the mean is x= 5.5. Let's use this value and apply the formula to each value in the set.
x_n | x_n-x | (x_n-x)^2 |
---|---|---|
8.2 | 8.2-5.5=2.7 | 2.7^2=7.29 |
10.1 | 10.1-5.5=4.6 | 4.6^2= 21.16 |
2.6 | 2.6-5.5=- 2.9 | (- 2.9)^2=8.41 |
4.8 | 4.8-5.5=0.7 | 0.7^2=0.49 |
2.4 | 2.4-5.5=- 3.1 | (- 3.1)^2=9.61 |
5.6 | 5.6-5.5= 0.1 | 0.1^2=0.01 |
7.0 | 7.0-5.5=1.5 | 1.5^2=2.25 |
3.3 | 3.3-5.5=- 2.2 | (- 2.2)^2=4.84 |
Sum of Values | 54.06 |
Finally, since n= 8, we need to divide by 8 and then calculate the square root. Standard Deviation: sqrt(54.06/8) ≈ 2.60