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If a measure of center is less than or greater than most of the data values, then it does not best represent the data.
Mean: 12.6
Median: 12
Mode: does not exist
Mean, see solution.
We want to find the mean, median, and mode of the given data set.
9, 10, 12, 15, 17 Let's proceed to finding the mean, median, and mode.The mean of a data set x is calculated by finding the sum of all of the values in the set and then dividing by the number of values in the set. In this case, there are 5.
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When the data are arranged in numerical order, the median is the middle value — or the mean of the two middle values. Let's arrange the given values and find the median. 9 , 10 , 12 , 15 , 17 The median of this set is 12.
The mode is the value or values that appear most often in a set of data. Let's find the mode of the given values. 12 , 9 , 17 , 15 , 10 Since the data set does not contain any repeated values, there is no mode.
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Mode & Median & Mean
* & ? & ?
Let's now consider the mean and the median. In the given list of numbers there are no obvious outliers. Also, neither the median nor the mean are greater or less than most of the values. Therefore, both the median and the mean could represent the data.
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Mode & Median & Mean
* & âś“ & âś“
In such case we usually choose the mean.