Big Ideas Math Algebra 1, 2015
BI
Big Ideas Math Algebra 1, 2015 View details
1. Solving Simple Equations
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Exercise 47 Page 9

Practice makes perfect
a Let x represent the discounted price of each CD. It is given that we buy 4 CDs and that the total we spend is $30.40
4x=30.40 Solving this equation for x will give us the discounted price of each CD.
4x=30.40
x=7.60
The solution x=7.60 means that the discounted price of one CD is $7.60.
b It is given in Part B that the CDs are no longer on sale. In order to determine if $25 is enough to buy 3 CDs, we must find the full price of one CD.

What is the full price of one CD?

In Part A, it was given that the price of CDs were discounted. In fact, we only paid 80 % of the original cost. We need to determine the full price of one CD. We know that $7.60 is 80 % of the original cost. If we let c represent the original cost, we can write the following equation. 7.60=0.80cSolving the equation for c will give us the full price of one CD.
7.60=0.80c
9.50=c
c=9.50
The solution c=9.50 means that the full cost of one CD is $9.50.

Is $25 enough for 3 CDs?

Now that we know the cost of one CD, we can determine the cost of three CDs by multiplying 9.50 by 3. 9.50 * 3 = 28.50 At full price, three CDs will cost $28.50. Thus, $25 is not enough.