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Let's start by recalling the slope-intercept form of a line. $\begin{gathered} y=m x+b \end{gathered}$ Here, $m$ is the slope and $b$ the $y\text{-}$intercept. We'll find these two values for the given line.

Consider the given graph.

The value of $b$ is given by the $y\text{-}$coordinate of the point at which the line intercepts the $y\text{-}$axis. We can see in the graph that the line intercepts the $y\text{-}$axis at $(0,2).$ This means that $b=2.$ $\begin{gathered} y=m x+2 \end{gathered}$

To find the slope, we will trace along the line on the given graph until we find a lattice point, which is a point that lies perfectly on the grid lines. By doing this, we will be able to identify the slope using the rise and run of the graph.

Here we have identified $(1,1)$ as our second point. Traveling to this point from the $y\text{-}$intercept requires $1$ step down and $1$ step to the right. $\begin{gathered} \dfrac{\text{rise}}{\text{run}} = \dfrac{\text{-}1}{1} \quad\Leftrightarrow\quad m= \text{-}1 \end{gathered}$ We can now write the complete equation of the line. $\begin{aligned} y=\text{-} x +2 \end{aligned}$

b

Consider the given graph.

Thus, the $y$-intercept is $b=\text{-}1$ and we can substitute it into the slope-intercept form. $\begin{gathered} y=mx-1 \end{gathered}$

The slope can be found by identifying the rise and run between two points on the line. We already know one point, the $y$-intercept. Let's now use a lattice point, a point that lies perfectly on the grid, as our second point.

We have identified $(2,0)$ as our second point. Traveling to this point from the $y\text{-}$intercept requires $2$ steps to the right and $1$ steps up. $\begin{gathered} \dfrac{\text{rise}}{\text{run}} = \dfrac{1}{2} \quad\Leftrightarrow\quad m = \dfrac{1}{2} \end{gathered}$ We can now write the complete equation of the line. $\begin{aligned} y=\dfrac{1}{2}x-1 \end{aligned}$