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{{ printedBook.courseTrack.name }} {{ printedBook.name }} We can plug in the given $x$-values into the inequality to determine if the inequality still holds true.

$3+4x<8−3x$

Substitute$x=-2$

$3+4(-2)<? 8−3(-2)$

MultiplyMultiply

$3−8<? 8+6$

AddSubTermsAdd and subtract terms

$-5<14$

Since the inequality holds, $x=-2$ is a solution. Let's try $x=0.$

$x=0$ is also a solution to the inequality. Lastly, let's check $x=1.$

$3+4x<8−3x$

Substitute$x=1$

$3+4⋅1<? 8−3⋅1$

MultiplyMultiply

$3+4<? 8−3$

AddSubTermsAdd and subtract terms

$7≮5$

This is not a solution to the inequality since $7$ is greater than $5.$ Thus, in summary, we have found two solutions: $x=-2andx=0.$