Both tangent and cotangent can be alternatively defined using sine and cosine.
Tangent is defined as in the following triangle.
By manipulating the right-hand side, it can be expressed as sine over cosine instead.
Cotangent is the reciprocal of tangent, leading to the following identity.
This identity can be shown using the Unit Circle and the Pythagorean Theorem. Consider a point on the Unit Circle in the first quadrant, corresponding to the angle A right triangle can be constructed with
By the Pythagorean Theorem, it follows that In fact, this is true for every point on the Unit Circle, not only for points in the first quadrant. Recall that, for points on the Unit Circle corresponding to the angle Substituting these into the previous equality gives the Pythagorean Identity, short of rearranging the terms: Note that represents and similarly for Dividing both sides by either or leads to two variations of the Pythagorean Identity.
Studying angles and their trigonometric values in a right triangle more closely reveals further relationships between sine and cosine, and between tangent and cotangent.
The angles in a right triangle, expressed in radians, is the unknown and The third angle comes from that the sum of the angles in a triangle is
Cosine of can now be expressed using the angle's adjacent side and the hypotenuse: Sine of the opposite angle can be similarly expressed as As the right-hand sides are equal, so must the left-hand sides be, leading to the identity.
This identity is true for all angles, not just those possible to construct in a right triangle.
Using similar reasoning, the following two identities can also be found.
Given that and find the values of and without determining
To begin, we can find the value of using the Pythagorean Identity. By substituting we get an equation that is solvable for the value of
Notice that there are two values for From the prompt, we know that must be between and corresponding to the first quadrant on the Unit Circle. For these angles, is positive. Thus, the negative solution can be discarded. Using the sine and cosine values, can be found.
The remaining values are the reciprocals of the ones we've found so far. Thus, we can swap the numerator with the denominator for the fractions to find the desired values. As the tangent value isn't expressed as a fraction, it can simply be substituted. We have now found all the desired values.