{{ item.displayTitle }}

No history yet!

Student

Teacher

{{ item.displayTitle }}

{{ item.subject.displayTitle }}

{{ searchError }}

{{ courseTrack.displayTitle }} {{ statistics.percent }}% Sign in to view progress

{{ printedBook.courseTrack.name }} {{ printedBook.name }} a

We could solve this exercise in two ways. Either, start with calculating $g(100),$ which equals the number we should raise $10$ to in order to get $100.$ Therefore, $g(100)$ is equal to $2,$ which is $10_{log(100)}=10_{2}=100.$ We could also use the inverse properties of logarithms. They say that that a power and a logarithm with the same base undo each other, or $10_{log(a)}=a.$ We then immediately see that $10_{log(100)}=100.$

b

In order to get the number $72,$ we raise $10$ to the $g(72)_{th}$ power. But what do we actually get if you raise $10$ to that? Well, we get $72.$ $10_{log(72)}=72$

c

It doesn't matter that there is a decimal number in the logarithm. The same rule applies. $10_{log(1.3)}=1.3$