Using Properties of Logarithms

We could solve this exercise in two ways. Either, start with calculating $\log (100),$ which equals the number we should raise $10$ to in order to get $100.$ Therefore, $\log (100)$ is equal to $2,$ which is $$10^{\log (100)}=10^2=100.$$ We could also use the inverse properties of logarithms. They say that that a power and a logarithm with the same base undo each other, or $10^{\log (a)}=a.$ We then immediately see that $$10^{\log (100)}=100.$$

In order to get the number $72,$ we raise $10$ to the $\log (72{)}^{\text{th}}$ power. But what do we actually get if you raise $10$ to that? Well, we get $72.$ $$10^{\log (72)}=72$$

It doesn't matter that there is a decimal number in the logarithm. The same rule applies. $$10^{\log (1.3)}=1.3$$