{{ item.displayTitle }}

No history yet!

Student

Teacher

{{ item.displayTitle }}

{{ item.subject.displayTitle }}

{{ searchError }}

{{ courseTrack.displayTitle }} {{ statistics.percent }}% Sign in to view progress

{{ printedBook.courseTrack.name }} {{ printedBook.name }} In order for $(1,4)$ to be a solution to the system of inequalities, we have to shade the region to the right of both inequalities. Let's do that and see what happens.

Let's isolate the shading where both inequalities apply.

Thus, this is the correct area since $(1,4)$ is in the shaded area but not the other three points. We should now find the correct inequality signs buy substituting $(1,4)$ into the boundary lines.$y22 -3x+2$

$422 -3⋅1+2$

$422 -1$

$\begin{cases}y \ \fbox{\geq} \ \text{-} 3x+2 \\ y \ \fbox{\geq} \ x+2 \end{cases}$