MathReads
Get Premium
Dashboard

Dashboard Sign out
A1
Algebra 1 View details
4. Solving Systems of Inequalities
Continue to next lesson
Lesson
Exercises
Tests
arrow_back
eCourses /
Algebra 1 /
Chapter 5
4. 

Solving Systems of Inequalities

Solving systems of inequalities involves finding regions where multiple inequalities overlap on a graph. These systems can be visualized by plotting each inequality on the same coordinate plane. The overlapping region represents the solution set of the system. For instance, when considering Jordan's situation of managing her budget while buying gifts, a system of inequalities can represent the possible number of items she can purchase without exceeding her budget. Similarly, when planning a travel route, the total distance and time can be represented through inequalities to ensure the journey meets specific criteria. Graphing these inequalities helps in visualizing the feasible solutions and making informed decisions.
Show more expand_more
Problem Solving Reasoning and Communication Error Analysis Modeling Using Tools Precision Pattern Recognition
Lesson Settings & Tools
10 Theory slides
15 Exercises - Grade E - A
Each lesson is meant to take 1-2 classroom sessions
Image Credits expand_more
Solving Systems of Inequalities
Slide of 10
Every individual benefits from the efficient use of their resources such as time and money. To use such resources effectively, several inequalities might need to be solved simultaneously. Together, these inequalities form a system. This lesson will teach how to write systems of inequalities and how to solve them using graphs.

Catch-Up and Review

Here are a few recommended readings before getting started with this lesson.

Challenge

Matching Graphs With Inequalities

Each of the following graphs represents the solution set of a certain inequality.

Five different coordinate planes with a line and a region shaded

Pair each graph with its corresponding inequality.

Explore

Analyzing Plane Regions Formed by Two Inequalities

In the following applet, each of the solution sets of the inequalities presented previously can be viewed on the same coordinate plane. Plane regions are formed once two inequalities are drawn. Only two can be drawn at a time.
A coordinate plane and 5 buttons to display five different inequalities. Only two inequalities can be seen at the same time
Think about what each of these regions — overlapping, shaded, and unshaded — represent.
Discussion

System of Linear Inequalities

As seen earlier, when two or more inequalities are graphed on the same coordinate plane, their solution sets may overlap. In these cases, the set of all inequalities being solved simultaneously forms a system of inequalities.

Concept

System of Inequalities

A system of inequalities is a set of two or more inequalities involving the same variables. For example, the set formed by the following two inequalities is a system.
The solution set of a system of inequalities is the set of all ordered pairs that satisfy all the inequalities in the system simultaneously. The ordered pair for example, is a solution to the above system.
Usually, systems of inequalities are solved by graphing each inequality on the same coordinate plane. When the inequalities in a system are graphed, the coordinate plane is divided into different regions. These regions provide an insight into the determination of the solution set. To see what these regions represent for the aforementioned system, move point
Two lines graphed and four regions
Of the regions formed, the overlapping region represents the solution set of the system.
Method

Solving a System of Linear Inequalities Graphically

A system of linear inequalities can be solved by graphing all inequalities on the same coordinate plane and then finding the region of intersection, if any. For example, consider the following system.
To solve the system graphically, these three steps can be followed.
1
Write the Inequalities in Slope-Intercept Form
expand_more
To simplify the process of graphing the inequalities, start by writing them in slope-intercept form.
SubIneq

SubIneq

DivIneq

2
Graph the Inequalities
expand_more
To graph the inequalities, begin with writing the corresponding boundary lines. The boundary line of the first inequality is
Since the inequality is strict, the boundary line should be dashed and, in this case, the shaded region is the one below the line.
Drawing y=-x+7 dashed and the region below it is shaded
Similarly, the boundary line of the second inequality is
Since the inequality is non-strict, its boundary line is solid. In addition, the region to be shaded is the one below the line. This inequality will be graphed on the same coordinate plane.
Drawing y=-0.5x+5 solid and the region below it is shaded
3
Find the Overlapping Region
expand_more

Notice that there is a region where the solution sets of the inequalities overlap. All the points in this region satisfy both inequalities simultaneously. Therefore, the overlapping region is the solution set of the system. In the next graph, only the common region is shaded.

Since the boundary lines in their entirety are not part of the solution set, they can be cropped to show only the edges of the overlapping region, or the exceeding parts can be drawn with lower opacity.

Keep in mind that if there is no overlapping region, the system has no solution.
Example

Buying Gifts Without Going Over Budget

Jordan, feeling jolly, is thinking about giving gifts to her teammates — there are players. Shopping at a stationery store, she decides it is best to buy some fancy ballpoint and fountain pens. She wants to spend less than and is now unsure whether to give all or only some of her teammates a gift.

A ballpoint pen labeled for 6 dollars and a fountain pen labeled for 12 dollars

Let and be the number of ballpoint and fountain pens Jordan will buy, respectively.

a Help Jordan and write a system of inequalities that represents this situation.
b Graph the solution set of the system.
c If Jordan wants to buy the maximum number of fountain pens she can under her budget, what is the maximum number of teammates that could get a gift? How many of them will get a ballpoint pen?

Answer
a
b Graph:
Region enclosed by the lines y=30-x and y=20-0.5x and the first quadrant. Only points with integer coordinates
c A maximum of teammates could get a gift. Of that number, only one would get a ballpoint pen.

Hint
a Recall that Jordan can buy at most gifts and that the total cost has to be less than
b To graph the solution set of the system of inequalities, start by writing the inequalities in slope-intercept form. Note that only points with non-negative and integer coordinates are meaningful.
c Of the points in the solution set, which one has the greatest coordinate?

Solution
a Since Jordan has teammates, she can buy at most gifts. In other words, the sum of the number of ballpoint pens and the number of fountain pens can be at most This leads to writing the first inequality.
Jordan does not want to go over budget and wants to spend less than Therefore, the total cost of the pens has to be less than
The total cost equals the number of ballpoint pens bought multiplied by its price plus the number of fountain pens bought multiplied by its price. Using the fact that each ballpoint pen costs and each fountain pen costs a second inequality can be set.
In consequence, the following system of inequalities models Jordan's situation.
b To solve the system written in Part A graphically, both inequalities will be graphed on the same coordinate plane.
Start by rewriting each inequality in slope-intercept form. To do so, isolate the variable in the left-hand side of each inequality.
▼
Write in slope-intercept form
SubIneq

SubIneq

DivIneq

To graph inequality (I), first, draw the boundary line whose equation is Since the inequality is non-strict, the line is solid. In this case, the region to be shaded is the one below the line.
Line y=-x+30 drawn and the region below it shaded
Next, graph inequality (II) on the same coordinate plane. To do so, draw the boundary line whose equation is Since the inequality is strict, the line will be dashed. As before, the region to be shaded is the one below the line.
Line y=-0.5x+20 drawn and the region below it shaded
The solution to the system of inequalities is the overlapping region. However, since buying a negative number of pens does not make sense, the negative values should be discarded. Therefore, the shaded region will include but also be limited by the coordinate axes.
Region enclosed by the lines y=30-x and y=20-0.5x and the first quadrant
Additionally, buying ballpoint pens is nonsensical. Therefore, only points with integer coordinates are part of the solution. Consequently, the solution set of the system looks as follows.
Region enclosed by the lines y=30-x and y=20-0.5x and the first quadrant. Only points with integer coordinates.
c Since represents the number of fountain pens that Jordan will buy, in the solution of the system found in Part B, look for the points with the greatest coordinate.
Region enclosed by the lines y=30-x and y=20-0.5x and the first quadrant
As seen, in the shaded region, there are two points with the greatest integer coordinate — and Therefore, Jordan has two options, buying no ballpoint pens and fountain pens or buying one ballpoint pen and fountain pens.
0 pens and 19 fountain pens or 1 pen and 19 fountain pens

With the first option, teammates will receive a gift, while teammates will get a gift with the second option. Therefore, if Jordan buys the maximum number of fountain pens she can, the maximum number of teammates that could get a gift is Of those teammates, only one would get a ballpoint pen.

Example

Working Two Jobs Without Being Overworked

Jordan enjoyed being able to buy gifts for her friends. Now she wants to save up to buy a family members car. To achieve this goal, she dares to work two jobs this summer — one in a mechanic shop and another in a bakery. She can make per hour in the mechanic shop and per hour in the bakery.
In the mechanic shop: 9 dollars per hour; In the bakery: 8 dollars per hour.
Jordan plans to work every day for at least more hours in the bakery than in the mechanic shop. However, since she does not want to overwork, she does not plan to earn more than per day.
a Let and be the number of hours that Jordan will work in the mechanic shop and in the bakery every day, respectively. Write a system of inequalities that models Jordan's situation.
b Solve the system graphically.
c Last Friday, Jordan worked whole number of hours in both places. What is the minimum amount of money she could have earned last Friday?

Answer
a
b Graph:
Region enclose by the y-axis and the lines y=x+4 and y=-9/8x+13.5
c

Hint
a Note that must be greater than or equal to Also, be aware that Jordan plans to earn at most per day.
b Both boundary lines have to be drawn solid, and negative values do not make sense.
c Look for the points with integer coordinates inside the region drawn in Part B. Which of these points is farthest from the line representing the maximum daily earnings? Use the coordinates of that point to determine the amount of money earned.

Solution
a Since Jordan wants to work in the bakery at least more hours than in the mechanic shop, must be greater than or equal to plus
On the other hand, it is said that Jordan plans to earn no more than That is, her daily income is at most
The daily income equals the hourly rate multiplied by the number of hours worked. Since Jordan has two jobs, her daily income equals multiplied by the number of hours worked in the mechanic shop added to multiplied by the number of hours worked in the bakery.
Consequently, the following system of inequalities models Jordan's situation.
b To solve the system written in Part A graphically, both inequalities will be graphed on the same coordinate plane.
The first inequality is already in slope-intercept form. However, the other inequality needs to be written in slope-intercept form.
▼
Write in slope-intercept form
SubIneq

DivIneq

To graph inequality (I), its boundary line will be drawn first. Since the inequality is non-strict, the line is solid. Since does not satisfy the inequality, the region to be shaded is the one not containing the origin.
Line y=x+4 drawn and the region above it shaded
Next, inequality (II) will be graphed on the same coordinate plane. To do so, draw the boundary line, whose equation is Since the inequality is non-strict, this line will also be solid. In this case, the region to be shaded is the one below the line.
Line y=x+4 drawn and the region above it shaded
The solution to the system of inequalities is the overlapping region. Notice that negative values do not make sense in this context. Therefore, the shaded region will include but also be limited by the axis. Consequently, the system's solution looks as follows.
Region enclose by the y-axis and the lines y=x+4 and y=-9/8x+13.5
c It is given that Jordan worked an integer number of hours in both jobs last Friday. Then, look for the points with integer coordinates inside the shaded region drawn in Part B. Since the points on the axis represent the case where Jordan did not work in the mechanic shop, these points should not be considered.
Region enclose by the y-axis and the lines y=x+4 and y=-9/8x+13.5
Because the second line drawn represents Jordan's maximum possible daily income, the further a point is from this line, the lower the income that the point represents. Of the points, the one that is farthest from the line is which represents the case when Jordan worked hour in the mechanic shop and hours in the bakery.
With this combination of worked hours, the minimum income that Jordan could have earned last Friday can be found. To do so, substitute and into the expression representing the daily income.
▼
Substitute coordinates and evaluate
SubstituteII

,

Multiply

Multiply

AddTerms

Add terms

Consequently, the minimum amount of money that Jordan could have earned last Friday is
Example

A Cinema's Expected Attendance and Revenue

Jordan now has a bit of extra cash to spend. She is excited for a new movie release. Ticket prices vary depending on the customer's age — for children and for adults. The cinema expects more than people to attend the premiere but they do not expect a revenue of more than
A ticket with the prices: Adults (9 dollars), Children (6 dollars)
Jordan finds herself wanting to solve this problem during her break time at the bakery. Let and be the number of children and adults who attended the movie premiere, respectively.
a Write a system of inequalities that models the given situation.
b Solve the system graphically.
c If the cinema's expectations were met and children attended the premiere, what is the maximum and minimum possible number of adults who could have attended the premiere?

Answer
a
b Graph:
Region enclose by the y-axis and the lines y=-x+250 and y=-2/3x+300
c Maximum:

Minimum:

Hint
a The number of attendees is greater than The cinema's revenue is less than or equal to
b The line representing the attendance is dashed while the other line is solid. In this context, only non-negative and integer values for and make sense.
c Look for the points whose coordinate is and lie inside the shaded region drawn in Part B. Of those points, what is the maximum integer coordinate?

Solution
a Since the cinema expects an attendance of more than people, the number of children plus the number of adults must be greater than
Also, it is said that the estimated revenue will be no more than Therefore, the revenue is less than or equal to
The cinema's revenue equals the number of children who attended the premiere multiplied by added to the number of adults who attended the premiere multiplied by
Consequently, the following system of inequalities models the described situation.
b To solve the system written in Part A graphically, both inequalities will be graphed on the same coordinate plane.
First, rewrite each inequality in slope-intercept form.
▼
Write in slope-intercept form
SubIneq

SubIneq

DivIneq

SimpQuot

Simplify quotient

To graph inequality (I), draw the boundary line whose equation is Since the inequality is strict, the line is dashed. In this case, the region to be shaded is the one above the line.
Line y=-x+250 drawn and the region above it shaded
Next, graph inequality (II) on the same coordinate plane. To do so, draw the boundary line whose equation is Since the inequality is not strict, this line will be drawn solid. In this case, the region to be shaded is the one below the line.
Line y=-2/3x+300 drawn and the region below it shaded
The solution to the system of inequalities is the overlapping region. However, because of the context, only non-negative and integer values make sense. Therefore, the region where both inequalities overlap will also be limited by the axes, including them.
Region enclose by the y-axis and the lines y=-x+250 and y=-2/3x+300
Instead of showing each point separately on the graph, because it is difficult to do so, the region where these points lie is shown. However, remember that only the points with integer coordinates are meaningful.
c It is known that the expected conditions have occurred.
  • More than people attended the premiere.
  • Less than was earned.
Recall that these two conditions were written as a system of inequalities and solved graphically.
The solution set of the system shows all the possible cases satisfying both conditions. Now, knowing that there were children in the premiere eliminates most of the possible cases.
Region enclose by the y-axis and the lines y=-x+250 and y=-2/3x+300
The number of adults who could have attended the premiere can be any point whose coordinate is and lie inside the shaded region. Of those points, has the the maximum integer coordinate and has the minimum coordinate.
Therefore, the number of adults who could have attended the premiere is any number between and inclusive.
Example

Analyzing a Road Trip Plan

Finally, Jordan was able to save enough money to buy a used car! She now plans to take a mini-road trip to visit a relative across-state. First, she will pick up her sister Ramsha, who lives in a different city. The travel distance depends on the path she chooses, but the entire route is no less than kilometers. Jordan would like to drive for a maximum of hours.

A map with a car and two roads to get to Ramsha's house and two more roads to get to Jordan's parents house.

Jordan plans to drive at kilometers per hour from her house to Ramsha's, and from there, she plans to increase the speed to kilometers per hour until reaching her relative's house.

a Let be the time it takes Jordan to drive from her house to Ramsha, and let be the time it takes to drive from Ramsha's house to her relative's house. Write a system of inequalities that models Jordan's travel plan.
b Solve the system graphically.

Answer
a
b The system has no realistic solution — the regions do not intersect in the first quadrant.
Region below the line y=7-x and above the line y=9 - 7/11x. These regions do not intersect n the first quadrant

Hint
a The sum of the traveling times cannot be greater than When speed is multiplied by time, the distance traveled is obtained. That is, Note that the sum of the distances is greater than or equal to kilometers.
b Both boundary lines have to be drawn solid. Note that negative values do not make sense.

Solution
a Since Jodran wants to drive at most for hours, the sum of the times, and should be at most With this, the first inequality can be written.
On the other hand, it is said that the entire route is no less than kilometers, which means that the distance to drive is greater than or equal to kilometers.
This distance can be written in terms of and by using the speed formula According to Jordan's plan, she will drive to Ramsha's house at a rate of kilometers per hour. Multiplying this rate by the time elapsed to arrive at Ramsha's house gives the distance traveled from her house to Ramsha's.
Similarly, multiplying the second rate, kilometers per hour, by the time it takes for the rest of the route, the distance from Ramsha's house to their relative's will be obtained.
The sum of these distances equals the distance needed to drive. Thus, a second inequality can be set.
These two inequalities need to be satisfied simultaneously. Therefore, the two inequalities together form a system of inequalities that models Jordan's travel plan.
b To solve the system written in Part A graphically, both inequalities will be graphed on the same coordinate plane.
First, rewrite the inequalities in slope-intercept form.
▼
Write in slope-intercept form
SubIneq

SubIneq

DivIneq

SimpQuot

Simplify quotient

To graph inequality (I), draw the boundary line Since the inequality is not strict, the line is dashed. In this case, the region to be shaded is the one below the line.
Region below the line y=7-x shaded
Next, graph inequality (II) on the same coordinate plane. To do so, first draw the boundary line Since the inequality is not strict, this line will also be drawn solid. However, the region to be shaded is the one above the line.
Region below the line y=7-x and above the line y=9 - 7/11x. These regions do not intersect n the first quadrant
The solution to the system of inequalities is the overlapping region. However, in the context of the given situation, and cannot take negative values as they represent time. Therefore, only solutions in the first quadrant, if any, should be considered.
Region below the line y=7-x and above the line y=9 - 7/11x. These regions do not intersect n the first quadrant
As seen, the system of inequalities has no realistic solution, which means Jordan's plan is not feasible. She will not be able to meet her travel expectations. For a more realistic plan, she should either increase the traveling speed or increase the maximum time she plans to drive. The second option is the safest, though.
Pop Quiz

Solving Systems of Linear Inequalities Graphically

For each given system of linear inequalities, select the region corresponding to its solution set, if any.

Random systems of linear inequalities and different regions shaded
Closure

Systems With More Than Two Inequalities

When working with a system of inequalities, there is no upper limit to the number of inequalities that can be analyzed. Consider, for example, the following system with three inequalities.
The steps to solve this system are the same as those used to solve a system with only two inequalities. The inequalities in the given system can be rewritten as follows.
The second step can be performed with the help of the applet.
Graphing the inequalities y greater than or equal to 3/4x-2, y greater than -2x-6, and y less than or equal to -0.25x+1
As can be seen, there is a portion of the plane where the three regions overlap — the triangle in the middle. Any point in that triangle is in the solution set of the system.
Region enclosed by the lines y=3/4x-2, y=-2x-6, and y=-1/4x+1. Triangle formed in the middle.
Note that in the examples considered throughout this lesson, even though only two inequalities were mentioned, the fact that the and values could not be negative is equivalent to considering the inequalities and That is, in those examples, four inequalities were considered together.



Level 1
Level 2
Level 3
Solving Systems of Inequalities
Exercises
Consider the following system of inequalities.
Which of the following is the solution set of the system of inequalities?
Four different coordinate planes with a line and a region shaded

To determine which of the options is the solution set, let's graph the system of inequalities. y ≤ 2x-2 & (I) y > - x -4 & (II) Note that both inequalities are written in slope-intercept form. Let's plot the first inequality. To do this, we first identify the corresponding boundary line. ccc Inequality & & Boundary Line y ≤ 2x-2 & & y = 2x-2 To determine which region to shade, we will test (0,0) in the inequality.

We got a false statement. Therefore, the region to be shaded is the one not containing the origin. Remember, since the inequality is non-strict we will draw the boundary line solid. We are now ready to plot our first inequality.

Next, let's plot the second inequality. Again, we start by writing its boundary line. ccc Inequality & & Boundary Line y > - x -4 & & y = - x -4 As before, to determine which region to shade let's test (0,0) in the inequality.

We got a true statement, which implies that the we have to shade the region containing the origin. Since the second inequality is strict, the boundary line is dashed. Let's graph this inequality on the same coordinate plane we graphed the first inequality.

Finally, let's graph only the solution set of the system of inequalities — the overlapping region.

Comparing the solution set we got with the four given ones, we conclude that the correct choice is option C.

Consider the following system of inequalities.
Which of the following plane regions describes the solution set of the system of inequalities?

To determine which of the regions describes the solution set, let's graph the system of inequalities. y > 2x + 3 & (I) y > 2x - 1 & (II) The first thing we note is that both inequalities are already written in slope-intercept form. Let's continue by writing the equations of the boundary lines. ccc Inequality & & Boundary Line [0.5em] y > 2x + 3 & & y = 2x + 3 [0.25em] y > 2x - 1 & & y = 2x - 1 A second thing to note is that both boundary lines have the same slope, which means that the lines are parallel. Also, both inequalities are strict, so we will draw both boundary lines dashed.

Let's focus for a moment on the first inequality. To determine which region to shade, we will test (0,0) in the first inequality.

We got a false statement. Therefore, we have to shade the region not containing the origin — the region above the line y=2x+3.

In a similar fashion, let's test (0,0) in the second inequality to determine which region to shade.

We got a true statement. Therefore, we have to shade the region containing the origin — the region above the line y=2x-1.

Finally, let's graph only the solution set — the overlapping region.

Consequently, option C describes the solution set of the system of inequalities. Option C The region above the liney=2x+3 without including it.

Consider the following plane regions.
Which of these regions describes the solution set of the following system of inequalities?

To determine which of the regions describes the solution set, let's graph the system of inequalities. y < 12x + 4 [0.1cm] y ≤ 12x -2 The first thing we note is that both inequalities are already written in slope-intercept form. Let's continue by writing the equations of the boundary lines. ccc Inequality & & Boundary Line [0.5em] y < 12x + 4 & & y = 12x + 4 [0.15cm] y ≤ 12x -2 & & y = 12x -2 A second thing to note is that both boundary lines have the same slope, which means that the lines are parallel. Since the first inequality is strict, we will draw the first boundary line dashed. In contrast, the second inequality is non-strict and therefore, we will draw the second boundary line solid.

Let's focus for a moment on the first inequality. To determine which region to shade, we will test (0,0) in the first inequality.

We got a true statement. Therefore, we have to shade the region containing the origin — the region below the line y= 12x+4.

In a similar fashion, let's test (0,0) in the second inequality to determine which region to shade.

We got a false statement. Therefore, we have to shade the region not containing the origin — the region below the line y= 12x-2.

Finally, let's graph only the solution set — the overlapping region.

Consequently, option B describes the solution set of the system of inequalities. Option B The region below the liney= 12x-2, including it.

Consider the following plane regions.
Which of these regions describes the solution set of the following system of inequalities?

To determine which of the regions describes the solution set, let's graph the system of inequalities. y ≥ 13x - 4 [0.1cm] y ≤ 13x + 3 The first thing we note is that both inequalities are already written in slope-intercept form. Let's continue by writing the equations of the boundary lines. ccc Inequality & & Boundary Line [0.5em] y ≥ 13x - 4 & & y = 13x - 4 [0.15cm] y ≤ 13x + 3 & & y = 13x + 3 A second thing to note is that both boundary lines have the same slope, which means that the lines are parallel. Also, both inequalities are non-strict which means that we have to draw both boundary lines solid.

Let's focus for a moment on the first inequality. To determine which region to shade, we will test (0,0) in the first inequality.

We got a true statement. Therefore, we have to shade the region containing the origin — the region above the line y= 13x-4.

In a similar fashion, let's test (0,0) in the second inequality to determine which region to shade.

We got a true statement. Therefore, we have to shade the region containing the origin — the region below the line y= 13x+3.

Finally, let's graph only the solution set — the overlapping region.

Comparing this region to the four given descriptions, we conclude that option A describes the solution set of the system of inequalities. Option A The region between the linesy= 13x-4 andy= 13x+3, including both lines.

Consider the following system of inequalities.
Which of the following claims is true about the system of inequalities?

To determine which of the claims is true about the system of inequalities, let's solve it graphically. y ≤ x - 1 y > x + 1 The first thing we note is that both inequalities are already written in slope-intercept form. Let's continue by writing the equations of the boundary lines. ccc Inequality & & Boundary Line [0.5em] y ≤ x - 1 & & y = x - 1 y > x + 1 & & y = x + 1 A second thing to note is that both boundary lines have the same slope, which means that the lines are parallel. Since the first inequality is non-strict, we will draw the first boundary line solid. In contrast, the second inequality is strict and therefore, we will draw the second boundary line dashed.

Let's focus for a moment on the first inequality. To determine which region to shade, we will test (0,0) in the first inequality.

We got a false statement. Therefore, we have to shade the region not containing the origin — the region below the line y=x-1.

In a similar fashion, let's test (0,0) in the second inequality to determine which region to shade.

We got a false statement. Therefore, we have to shade the region not containing the origin — the region above the line y=x+1.

As we can see, the individual solution sets do not overlap each other. This means that the system of equations has no solutions. Consequently, option D is the true statement about the system. Option D The system has no solution.

Determine if the point is a solution to the system whose solution is graphed.

Let's plot the point (- 2, - 2) in the given coordinate plane. If it lies in the shaded area, then the ordered pair is a solution of the system of inequalities.

Since the point lies within the shaded area, the ordered pair (- 2,- 2) is a solution to the system of linear inequalities.


We will plot the point (-2,-2) in the same coordinate plane as the system.

The point is not in the shaded region, and thus it is not a solution to the system of inequalities.

Is a solution to the following system?

When determining if a given point satisfies an equation, we substitute the point into the equation and simplify. If the resulting statement is true, then the point is contained in the solution set of the equation.

Example Equation: y=x+1
Point Substitution Solution?
( 1, 0) 0 &? = 1+1 0 &= 2 * No
( 0, 1) 1 &? = 0+1 1 &= 1 ✓ Yes

For systems of inequalities, we can use the same method. However, substituting the point must create true statements in every inequality of the system. Let's test (3,11) to see if it is a solution to the given system.

Since 11 is greater than 7 and less than 17, both statements are true. Therefore, the point (3,11) is a solution to the given system.

Graph the following system of inequalities and calculate the area of the solution set.

Let's graph each of the inequalities on the same coordinate plane. To start, note that each of the inequalities is already written in slope-intercept form. y ≥ 2 y ≤ x +5 y ≤ - x +5

Inequality (I)

In order to graph an inequality, we start by graphing the boundary line. A boundary line can be written by replacing the inequality symbol with an equals sign. ccc Inequality & & Boundary Line y ≥ 2 & & y = 2 The boundary line of the inequality is y=2, which is a horizontal line whose y-intercept is 2. Notice that the line is solid because the inequality is not strict.

To know which region to shade, let's test (0,0) in the inequality.

Since we got a false statement, (0,0) is not in the solution set of the first inequality. Therefore, let's shade the region above the line.


Inequality (II)

Let's start by determining the boundary line. ccc Inequality & & Boundary Line y ≤ x+5 & & y = x+5 Because the inequality is not strict, we will draw the boundary line solid.

As before, let's test (0,0) in the inequality to determine which region to shade.

Since the origin satisfies the inequality, we will shade the region containing the point (0,0). We will graph this inequality on the same coordinate plane where we graphed the first inequality.


Inequality (III)

In the same manner as before, let's determine the boundary line for the third inequality. ccc Inequality & & Boundary Line y ≤ - x+5 & & y = - x+5 Once again, let's test the point (0,0) in this third inequality.

Since (0,0) satisfies the inequality, we will shade the region containing the origin. This boundary will be solid as well because the inequality is not strict. Let's add it to the same coordinate plane as the first two inequalities.


Graphing the Solution Set

Next, let's graph only the solution set to the given system of inequalities — that is, let's remove the parts that are not common for the three regions.


Finding the Area of the Solution Set

The solution set is a triangle. To calculate its area, we need to determine the base and height. Then, we can use the formula for the area of a triangle.

As we can see from the graph, the base is b=6 and the height is h=3. Let's find the area.

In the following diagram, a system of linear inequalities has been graphed.

Of the ordered pairs, and one does not belong with the others. Find the one that does not belong.

Let's plot the given points on the same coordinate plane as the system of inequalities.

When looking at the four points, the first thing we can notice is that R(0,-4) and S(-1,-6) lie squarely within the solution set, and the points Q(1,-2) and P(2,-4) rest on the boundary lines. Let's remember what it means when a line is dashed and when it is solid.

  • A solid line tells us that the inequality is not strict. Therefore, the points on the boundary line are solutions to the inequality.
  • A dashed line tells us that the inequality is strict. Therefore, the points on the boundary line are not solutions to the inequality.

With the above in mind, we can conclude that P(2,-4) is a solution to the system because it lies on a solid line. However, the point Q(1,-2), which lies on both a solid and a dashed line, is a solution to one of the inequalities but not a solution to the other. Therefore, Q(1,-2) does not belong with the others, as it is not in the solution set.

Solving Systems of Inequalities

Recommended exercises

To get personalized recommended exercises, please login first.
Return to lesson.