We want to solve the system
{3x−y=58x−y=20(I)(II)
using the . We then need to eliminate one of the variable terms by adding or subtracting the equations. We can see that the
y-terms in this system will eliminate each other if we subtract Equation (II) from Equation (I). Let's do that!
−3x−y8x−y-5x+0===520-15
We find
x by solving the resulting equation.
-5x+0=-15⇔x=3
We find
y by substituting the value of
x into either of the original equations and solve the resulting equation for
y. Let's use Equation (I).
3x−y=5
3⋅3−y=5
9−y=5
-y=-4
y=4
The solution to the system of equations is
(3,4).