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Solving Radical Equations
Choose Course
Algebra 2
Radical Functions
Solving Radical Equations
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Solving Radical Equations 1.5 - Solution
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Return to Solving Radical Equations
a
We square both sides to solve for
x
.
x
=
0
RaiseEqn
LHS
2
=
RHS
2
x
=
0
2
CalcPow
Calculate power
x
=
0
Now we test the solution by substituting
0
for
x
in the original equation.
x
=
0
Substitute
x
=
0
0
=
?
0
CalcRoot
Calculate root
0
=
0
The equality holds, so
x
=
0
is a solution of the equation.
b
We start by solving for
x
.
3
=
3
x
MultEqn
LHS
⋅
3
=
RHS
⋅
3
9
=
x
RearrangeEqn
Rearrange equation
x
=
9
RaiseEqn
LHS
2
=
RHS
2
x
=
9
2
CalcPow
Calculate power
x
=
8
1
We came to the result
x
=
8
1
.
But since we squared the equation, we need to test it in the original equation to make sure that it is not an
extraneous solution
.
3
=
3
x
Substitute
x
=
8
1
3
=
?
3
8
1
CalcRoot
Calculate root
3
=
?
3
9
CalcQuot
Calculate quotient
3
=
3
The equality holds, so
x
=
8
1
is a solution to the equation.