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{{ printedBook.courseTrack.name }} {{ printedBook.name }} Before we will try to solve the given simple quadratic equation let's recall the number of real solutions to a quadratic equation $x_{2}=d,$ depending on the sign of $d.$

- When $d>0,$ $x_{2}=d$ has two real solutions, $x=±d .$
- When $d=0,$ $x_{2}=d$ has one real solution, $x=0.$
- When $d<0,$ $x_{2}=d$ has no real solution.

Notice that in our case $d=-36,$ which is negative, so there are no real solutions to the given equation.