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equalizer
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Solving One-Step Equations
Choose Course
Algebra 1
One-Variable Equations
Solving One-Step Equations
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Exercise 1.6 - Solution
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Return to Solving One-Step Equations
a
To solve the equation we have to isolate
a
on one side. By adding
2
1
to both sides of the equality,
a
will be standing alone on the left-hand side.
-
2
1
+
a
=
8
5
AddEqn
LHS
+
2
1
=
RHS
+
2
1
a
=
8
5
+
2
1
ExpandFrac
b
a
=
b
⋅
4
a
⋅
4
a
=
8
5
+
8
4
AddFrac
Add fractions
a
=
8
9
b
To solve the equation we have to isolate
w
on one side. Thus, we want to cancel out
5
2
by subtracting it from both sides.
4
3
=
w
+
5
2
SubEqn
LHS
−
5
2
=
RHS
−
5
2
4
3
−
5
2
=
w
RearrangeEqn
Rearrange equation
w
=
4
3
−
5
2
To subtract the fractions they need to have the same denominator. Here, the lowest
common denominator
is
2
0
.
w
=
4
3
−
5
2
ExpandFrac
b
a
=
b
⋅
5
a
⋅
5
w
=
4
⋅
5
3
⋅
5
−
5
2
ExpandFrac
b
a
=
b
⋅
4
a
⋅
4
w
=
4
⋅
5
3
⋅
5
−
5
⋅
4
2
⋅
4
Multiply
Multiply
w
=
2
0
1
5
−
2
0
8
SubFrac
Subtract fractions
w
=
2
0
7
c
To isolate
k
we want to multiply both sides with
5
as it's the
inverse operation
of dividing by
5
.
-
5
k
=
1
0
7
MultEqn
LHS
⋅
5
=
RHS
⋅
5
-
k
=
1
0
7
⋅
5
MoveRightFacToNum
c
a
⋅
b
=
c
a
⋅
b
-
k
=
1
0
3
5
ChangeSigns
Change signs
k
=
-
1
0
3
5
ReduceFrac
b
a
=
b
/
5
a
/
5
k
=
-
2
7