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Start by forming the possible triangles.
1/19
It is given that the angle measures of a triangle are each a multiple of 12. We will find the probability that the triangle is equiangular. Recall that an equiangular triangle is a triangle such that all three interior angles are 60^(∘).
| Triangles | m∠1 | m∠2 | m∠3 | Sum of the Angles |
|---|---|---|---|---|
| Triangle I | 12 | 12 | 156 | 180 |
| Triangle II | 12 | 24 | 144 | 180 |
| Triangle III | 12 | 36 | 132 | 180 |
| Triangle IV | 12 | 48 | 120 | 180 |
| Triangle V | 12 | 60 | 108 | 180 |
| Triangle VI | 12 | 72 | 96 | 180 |
| Triangle VII | 12 | 84 | 84 | 180 |
As we can see, there are seven triangles with the smallest angle measure of 12. The next multiple of 12 is 24, so let's list all of the triangles with the smallest angle measure of 24.
| Triangles | m∠1 | m∠2 | m∠3 | Sum of the Angles |
|---|---|---|---|---|
| Triangle VIII | 24 | 24 | 132 | 180 |
| Triangle IX | 24 | 36 | 120 | 180 |
| Triangle X | 24 | 48 | 108 | 180 |
| Triangle XI | 24 | 60 | 96 | 180 |
| Triangle XII | 24 | 72 | 84 | 180 |
So far we have listed 12 triangles, 5 of which have the smallest angle measure being 24. We should repeat this procedure for all other multiples of 12, increasing the smallest angle measure by 12 every step.
| Smallest angle measure | No. of triangles |
|---|---|
| 12 | 7 |
| 24 | 5 |
| 36 | 4 |
| 48 | 2 |
| 60 | 1 |
Overall, there are nineteen possible triangles and one is equiangular. We can find the probability by dividing the number of favorable outcomes by the number of possible outcomes. Number of favorable outcomes/Number of possible outcomes=1/19