Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 9 Page 579

Pay close attention to how consecutive terms are related.

a_1=4 and a_n=a_(n-1) - n*(-1)^n

Practice makes perfect
We want to write a recursive formula for the given sequence. 4, 2, 5, 1, 6, ...

To do so we need to analyze how consecutive terms are related. Let's find their difference. ccccc a_2-a_1&=& 2-4 &=& - 2 [1.2em] a_3-a_2&=& 5-2 &=& 3 [1.2em] a_4-a_3&=& 1-5&=& - 4 [1.2em] a_5-a_4&=& 6-1&=& 5 [2em] ... & & ... & & ...

a_n-a_(n-1) = - n*(-1)^n

We can see above that the difference between consecutive terms is - n*(-1)^(n-1). Therefore, to obtain the value of the term in the n^(th) position, we need to subtract - n*(-1)^n from the previous term. With this information and knowing that the first term equals 4, we can write the recursive formula. a_1=4 and a_n=a_(n-1) - n*(-1)^n