Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 7 Page 579

Pay close attention to how the consecutive terms are related.

a_1=2 and a_n=-2a_(n-1)

Practice makes perfect
We want to write a recursive formula for the given sequence. 2, -4, 8, -16, ...

To do so we need to analyze how the consecutive terms are related. Let's find the quotient between each pair of consecutive terms. ccccc a_2/a_1&=& -4/2 &=& -2 [1.2em] a_3/a_2&=& 8/-4 &=& -2 [1.2em] a_4/a_3&=& -16/8&=& -2 [1.2em] ... & & ... & & ...

a_n/a_(n-1) = -2

We can see above that the quotient between the consecutive terms equals -2. Therefore, to obtain the value of the term in the n^(th) position, we need to multiply the previous term by -2. With this information and knowing that the first term equals 2, we can write the recursive formula. a_1=2 and a_n=-2a_(n-1)