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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

Mid-Chapter Quiz

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Exercise 6 Page 579

The given rule means that, after the first term of the sequence, every term a_n is the difference between the previous term a_((n-1)) and 2.

1, 5, 11, 19, and 29

Practice makes perfect

We are asked to write the first 5 terms of a sequence, given a recursive rule.

a_1&=1 a_n&=a_((n-1))+2n, for n>1 To do so, we will use a table.

n	a_n=a_((n-1))+2n	a_((n-1))+2n	a_n
1	a_1=1	-	1
2	a_2=a_(( 2-1))+2* 2	a_1+2* n= 1+2* 2	5
3	a_3=a_(( 3-1))+2* n	a_2+2* n= 5+2* 3	11
4	a_4=a_(( 4-1))+2* n	a_3+2* n= 11+2* 4	19
5	a_5=a_(( 5-1))+2* n	a_4+2* n= 19+2* 5	29

Therefore, the first 5 terms of the sequence are 1, 5, 11, 19, and 29.

Subchapter links

Exercises p.579